Serve a Page from Server - Function view

Specification

Responds to requests to the url `/sample-page` with a simple string response.

Prerequisites

* You need to have a django project called `django_sample` set up, as shown here: [Writing your first Django app, part 1: Creating a project - djangoproject.com](https://docs.djangoproject.com/en/4.0/intro/tutorial01/#creating-a-project)
* You need to have a django app `example` set up, as shown here: [Writing your first Django app, part 1: Creating the Polls app - djangoproject.com](https://docs.djangoproject.com/en/4.0/intro/tutorial01/#creating-the-polls-app)

Code

`example\urls.py`

```python
from django.urls import path  
import example.views as views  
  
urlpatterns = [
    ...
    path('sample-page', views.view_sample_page, name='sample_page'),  
]
```

`example\views.py`

```python
from django.http import HttpResponse  
  
def view_sample_page(request):  
    return HttpResponse("Welcome to the sample page!")
```

`django_sample\urls.py`

```python  
from django.urls import include, path  
  
urlpatterns = [  
    ...
    path('', include('example.urls')),  
]
```

Further reading

### Guides/Articles
[Writing your first Django app, part 1 - djangoproject.com](https://docs.djangoproject.com/en/4.0/intro/tutorial01/#write-your-first-view)

References

{
    "classes":
    [
        {
            "name" : "django.http.HttpResponse",
            "urls" : ["https://docs.djangoproject.com/en/4.0/ref/request-response/#httpresponse-objects"]
        }
    ],
    "functions":
    [
        {
            "name" : "django.urls.include",
            "urls" : ["https://docs.djangoproject.com/en/4.0/ref/urls/#include"]
        },
        {
            "name" : "django.urls.path",
            "urls" : ["https://docs.djangoproject.com/en/4.0/ref/urls/#path"]
        }
    ]
}

Problem Description

In your server back-end software, create a new accessible page (e.g. in `/sample-page`) that outputs something simple